BRAIN EXERSISE
Here i am posting some math based brain exercise, Just tease your brain....
(Answers are at the end..)
First question:
2 CATS + 1 DOG = 10
2 CATS + 2 DUCKS + 1 DOG = 22
2 DUCKS + CAT = 15
WHAT IS THE VALUE OF QUESTION MARK IF : 4 CATS + 1 DUCK + 2 DOGS = ?
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Second question:
Third question:
FORTH QUESTION:
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ANSWERS :-
1.TAKE SECOND EQUATION : 2 CATS + 2 DUCKS + 1 DOG = 22
= [2 CATS + 1 DOG] + 2 DUCKS = 22 ; HERE WE CAN REPLACE '2 CATS + 1 DOG' WITH 10 AS GIVEN IN FIRST EQUATION.
= 10 +2 DUCKS = 22
= 2 DUCKS = 22-10 =12
= 1 DUCK = 12\2=6
SO,1 DUCK= 6
NEXT IF WE MOVE TO THIRD EQUATION: 2 DUCKS + 1 CAT = 15 ; HERE WE CAN REPLACE '2 DUCKS' WITH 12[6 X 2] WHICH WE GOT FROM SECOND EQUATION.
= 12 + 1 CAT= 15
= 1 CAT = 15-12=3
SO,1 CAT = 3
NOW WE NEED THE VALUE OF DOG SO, TO GET THIS VALUE, WE WILL PLACE THE VALUE OF CAT IN FIRST EQUATION,SO WE CAN GET THE VALUE OF DOG
2 CATS+ 1 DOG =10
[2 X 3] + 1 DOG =10
6 + 1 DOG =10
1 DOG = 10-6=4
SO,1 DOG = 4
NEXT WE WILL PLACE THE VALUE OF DOG,CAT AND DUCK IN THE QUESTION; 4CATS +1 DUCK +2 DOGS=[3 X 4]+6+[2 X 4]
= 12+6+8
= 26
SO 26 IS THE ANSWER.GOT IT?
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2.THE ANSWER IS 36
SOLUTION IS:-
[WE SHOULD MULTIPLY THE NUMBERS IN THE DOWN SIDE] AND ADD TO [THE SUM OF THE SUM OF NUMBERS IN THE TOP]
-[THIS IS THE FORMULA USED TO FIND THE NUMBER IN THE SQUARE].
IF WE TAKE THE FIRST SQUARE:
[7 INTO 11] + [4 + 5]
= 77 + 9
= 86.
<SO WE CAN PROVE THAT THIS FORMULA WORKS{WE CAN FIND THE FORMULA BY CHECKING LIKE THIS,WE CAN FIND ANY MAGIC SQUARE LIKE THIS}.
NOW, IF WE TAKE THE FORTH SQUARE FOR WHICH THE ANSWER IS ASKED WE SHALL FIND THE ANSWER :
[3 INTO 1] + [ 15 + 18 ]
= 3 + 33
= 36
< SO THE ANSWER IS 36.
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3.THE ANSWER IS 14
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FOR EASY EXPLANATION IF WE CONVERT THE PICTURES INTO WORDS IT WOULD BE EASY SO IF WE TAKE THE QUESTION IN WORDS IT WOULD BE LIKE THIS:
TIGER + CAT = CRAYONS + 1 --- (EQUATION 1)
FOX + TIGER + FOX = CAT --- (EQUATION 2)
0 = FOX X CRAYONS --- (EQUATION 3)
CRAYONS - 3 = 2 --- (EQUATION 4)
THEN, WHAT IS TIGER X CAT X + CRAYONS = ?
SOLUTION:
FIRST,
IF WE TAKE FOURTH EQUATION,
CRAYONS - 3 = 2
= CRAYONS - 3 + 3 = 2 + 3
= CRAYONS + 0 = 2 + 3
= CRAYONS = 5
NOW IF WE TAKE THIRD EQUATION,
THE VALUE OF EITHER FOX OR CRAYONS SHOULD BE 0 BECAUSE,AS THE ANSWER IS 0 FOR THIS EQUATION AND ANY MULTIPLICATION OF NUMBERS WITHOUT 0 IN ONE OF NUMBERS,THE ANSWER CANT BE 0.
AS, WE KNOW THE VALUE OF CRAYONS IS 5 FROM FORTH EQUATION, THE VALUE OF FOX SHOULD BE 0.
NOW IF WE TAKE SECOND EQUATION,
FOX + TIGER + FOX = CAT
= 0 + TIGER + 0 = CAT
= TIGER = CAT
FROM THIS EQUATION WE CAN KNOW THAT TIGER = CAT
NOW, IF WE TAKE FIRST EQUATION,
TIGER + CAT = CRAYONS + 1
= TIGER + CAT = 5 + 1
= TIGER +CAT = 6
AS,TIGER = CAT; WE DISPLACE CAT WITH TIGER [IF WE WANT WE CAN DISPLACE TIGER WITH CAT ALSO,YOU WILL GE THE SAME ANSWER]
SO,NOW: TIGER + TIGER = 6
= 2[TIGER] = 6
= TIGER =6\2 = 3
= TIGER = 3
SO,CAT = CAT = TIGER = 3
NOW,WE WILL SOLE THE QUESTION GIVEN:
TIGER X CAT + CRAYONS = ?
= 3 X 3 + 5 = ?
= ? = 9 + 5
= ? = 14
< SO THE ANSWER IS 14. THIS IS A BIG SOLUTION! ISN'T IT?
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4.THE ANSWER IS 17.
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SOLUTION:
I AM TAKING SMILING FACE AS HAPPY AND SAD FACE AS SAD;
FIRST,IF WE TAKE FIRST EQUATION:
HAPPY + HAPPY = 32
= 2[HAPPY] = 32
= HAPPY = 32\2 = 16
NOW IF WE PLACE THE VALUE OF HAPPY IN SECOND EQUATION:
SAD + HAPPY = 25
= SAD + 16 = 25
= SAD = 25 - 16
=SAD = 9
NOW,WE WILL SOLVE THE VALUE OF QUESTION MARK;
? + SAD + HAPPY + SAD = 51
= ? + 9 + 16 + 9 = 51
= ? + 34 = 51
= ? = 51 - 34
= ? = 17
< SO THE ANSWER IS 17.
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